4y^2+16y-30=0

Solution for 4y^2+16y-30=0 equation:

4y^2+16y-30=0

a = 4; b = 16; c = -30;
Δ = b2-4ac
Δ = 162-4·4·(-30)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{46}}{2*4}=\frac{-16-4\sqrt{46}}{8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{46}}{2*4}=\frac{-16+4\sqrt{46}}{8}
$